Trenger også hjelp med denne:
a / 2a-4 - a+1 / 3a - 6
algebra
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[tex]\frac{a}{2a-4}-\frac{a+1}{3a-6}=\frac{a(3a-6)}{(2a-4)(3a-6)}-\frac{(a+1)(2a-4)}{(3a-6)(2a-4)}[/tex]Turte wrote:Trenger også hjelp med denne:
a / 2a-4 - a+1 / 3a - 6
[tex]\frac{a(3a-6)}{(2a-4)(3a-6)}-\frac{(a+1)(2a-4)}{(3a-6)(2a-4)}= \frac{(3a^2)-(2a^2-4a+2a-4)}{(3a-6)(2a-4)}= \frac{a^2+2a+4}{6a^2-12a-12a+24}= \frac{(a-2)(a-2)}{6(a-2)(a-2)}= \frac{1}{6}[/tex]
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