Jeg trenger hjelp med denne oppgaven:
a^2-4 / 9 a^3 * 6a / a+2
algebra
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Dolandyret
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[tex]\frac{a^2-4}{9a^3}*\frac{6a}{a+2}=\frac{(a^2-4)(6a)}{(9a^3)(a+2)}=\frac{6a^3-24a}{9a^4+18a^3}=\frac{2a^2-8}{3a^3+6a^2}=\frac{2(a+2)(a-2)}{3a^2(a+2)}=\frac{2a-4}{3a^2}[/tex]Turte wrote:Jeg trenger hjelp med denne oppgaven:
a^2-4 / 9 a^3 * 6a / a+2
"I want to die peacefully in my sleep like my grandfather, not screaming in terror like his passengers."