Sjekk om min algebra-fu er sterk :)

[Noob11]

Jeg skal forenkle to uttrykk.

Den første:
[tex]\frac{(a^3)^{-1}2a^4}{(2a^{-1})^2}=>\frac{a^{-3}2a^4}{2^2a^{-2}}=>\frac{2a}{2^2a^{-2}}=>2a2^{-2}a^2=>2^{-1}a^3=>\frac{1}{2}a^3[/tex]

Den andre:

[tex]\frac{(2b)^{-1}^3\sqrt{ab}\sqrt{\frac{1}{2a}}}{\sqrt{ab2}a^{-2}}=>\frac{2^{-1}b^{-1}a^{\frac{1}{3}}b^{\frac{1}{3}}2^{-\frac{1}{2}}{a^{-\frac{1}{2}}}}{a^{\frac{1}{2}}ba^{-2}}=>2^{-1}b^{-1}a^{\frac{1}{3}}b^{\frac{1}{3}}2^{-\frac{1}{2}}a^{\frac{1}{2}}a^{-\frac{1}{2}}ba^2=>2^{(-1-\frac{1}{2})}a^{(\frac{1}{3}+\frac{1}{2}-\frac{1}{3}+2)}b^{(-1+\frac{1}{3}+1)}=>2^{-\frac{3}{2}}a^{\frac{5}{2}}b^{\frac{1}{3}}[/tex]

Ser dette nogenlunde riktig ut?