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Gjør uttrykket så enkelt som mulig(brøk)
Posted: 30/09-2012 16:42
by Quattro1
4b^(2)-(3b-3/2)(-3b/4)+1/4(b-b^(2))
Svaret skal vell bli: (b(48b-7))/(8)
men jeg trenger hjelp til utregning, slit med et eller anna fortegn/parantes
Posted: 02/10-2012 20:26
by Harvey Specter
[tex]4b^2 - (3b - \frac{3}{2})(-\frac{3b}{4}) + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 - (-\frac{9}{4}b^2 + \frac{9}{8}b) + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 +\frac{9}{4}b^2 - \frac{9}{8}b + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 + \frac {8}{4}b^2 - \frac{9}{8}b + \frac{2}{8}b[/tex]
[tex]6b^2 - \frac{7}{8}b[/tex]
Posted: 06/10-2012 19:28
by Quattro1
Harvey Specter wrote:[tex]4b^2 - (3b - \frac{3}{2})(-\frac{3b}{4}) + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 - (-\frac{9}{4}b^2 + \frac{9}{8}b) + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 +\frac{9}{4}b^2 - \frac{9}{8}b + \frac{1}{4}b - \frac{1}{4}b^2[/tex]
[tex]4b^2 + \frac {8}{4}b^2 - \frac{9}{8}b + \frac{2}{8}b[/tex]
[tex]6b^2 - \frac{7}{8}b[/tex]
Takker, ser jo at d blir d samme, bare at i mitt svar der oppe så er alt ganget opp til fellesnevner 8.