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logaritme likning

Posted: 19/10-2005 22:55
by a.m
Hvordan løser vi denne?

3e^(2x) - 2e^(x)=0

Posted: 19/10-2005 23:02
by Solar Plexsus
Tips: 3e[sup]2x[/sup] - 2e[sup]x [/sup] = e[sup]x[/sup] (3e[sup]x[/sup] - 2).