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Eksponentialulikhet

Posted: 12/10-2007 21:01
by matte:o)
Hvordan løser man denne?:

((1:10)^x) - 10 > 0

Re: Eksponentialulikhet

Posted: 12/10-2007 23:12
by ettam
[tex]((1:10)^x) - 10 > 0[/tex]

[tex](10^{-1})^x > 10^1[/tex]

[tex]10^{-x} > 10^1[/tex]

[tex]-x > 1[/tex]

[tex]\underline{\underline{x < -1}}[/tex]