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Eksponentialulikhet
Posted: 12/10-2007 21:01
by matte:o)
Hvordan løser man denne?:
((1:10)^x) - 10 > 0
Re: Eksponentialulikhet
Posted: 12/10-2007 23:12
by ettam
[tex]((1:10)^x) - 10 > 0[/tex]
[tex](10^{-1})^x > 10^1[/tex]
[tex]10^{-x} > 10^1[/tex]
[tex]-x > 1[/tex]
[tex]\underline{\underline{x < -1}}[/tex]