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				Eksponentialulikhet
				Posted: 12/10-2007 21:01
				by matte:o)
				Hvordan løser man denne?:
((1:10)^x) - 10 > 0
			 
			
					
				Re: Eksponentialulikhet
				Posted: 12/10-2007 23:12
				by ettam
				[tex]((1:10)^x) - 10 > 0[/tex]
[tex](10^{-1})^x > 10^1[/tex]
[tex]10^{-x} > 10^1[/tex]
[tex]-x > 1[/tex]
[tex]\underline{\underline{x < -1}}[/tex]