trigonometri
Posted: 29/09-2007 18:30
hey, hvordan skriver man
[tex]cos(\frac{5\pi}{6}[/tex] i brøkform?
[tex]cos(\frac{5\pi}{6}[/tex] i brøkform?
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Posted: 29/09-2007 18:56
[tex]\cos( \frac{5\pi}{6} ) = \cos( \pi - \frac \pi 6) = -\cos ( \frac \pi 6 ) = - \frac{\sqrt{3}}{2}[/tex]
Posted: 29/09-2007 19:07
tusen takk
Posted: 29/09-2007 21:23
Alternativt:
[tex]\cos(\frac{5\pi}{6})=\frac{\cos(\frac{5\pi}{6})}{1}[/tex]
[tex]\cos(\frac{5\pi}{6})=\frac{\cos(\frac{5\pi}{6})}{1}[/tex]
Posted: 29/09-2007 21:52
det var faktisk litt morro, jeg flirte