kjemi
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Leonhard_Euler
- Noether
- Posts: 24
- Joined: 26/03-2018 18:50
pH er definert som: [tex]-\lg([H_3O^+])[/tex]
Da har vi:
[tex]pH = -\lg([H_3O^+])[/tex]
[tex]-pH = \lg([H_3O^+])[/tex]
[tex]10^{-pH} = [H_3O^+][/tex]
Da har vi:
[tex]pH = -\lg([H_3O^+])[/tex]
[tex]-pH = \lg([H_3O^+])[/tex]
[tex]10^{-pH} = [H_3O^+][/tex]
[tex]\ln(-1)=i\pi[/tex]