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Lagt inn: 01/06-2021 00:15
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oppg 12)
uten CAS:
[tex]f(x,y)=x^2+y^2+7x+4y+13\\ og\\ x+y=3\\[/tex]
[tex]y=3-x[/tex]
der
[tex]g(x)=(3-x)^2+x^2+7x+4(3-x)+13\\[/tex]
for å finne min/Max, deriveres g og settes lik 0:
[tex]g ' =-2(3-x)+2x+7-4 =0\\ \\ 4x=3\\ \\x=3/4\\ og\\ y=9/4[/tex]
endelig:
[tex]f(0.75, \,2.25)=32.9[/tex]