Hvordan løser vi denne?
lg x^3 + 2lg3x = 4
Logaritmisk ligning
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
-
- Over-Guru
- Innlegg: 1685
- Registrert: 03/10-2005 12:09
Nå er
lg x[sup]3[/sup] + 2 lg 3x = lg x[sup]3[/sup] + lg (3x)[sup]2[/sup] = lg x[sup]3[/sup] + lg 9x[sup]2[/sup] = lg (x[sup]3[/sup]*9x[sup]2[/sup]) = lg 9x[sup]5[/sup], dvs. at
lg 9x[sup]5[/sup] = 4
9x[sup]5[/sup] = 10[sup]4[/sup]
x[sup]5[/sup] = 10[sup]4[/sup]/9
x = (10[sup]4[/sup]/9)[sup]1/5[/sup] ≈ 4,07.
lg x[sup]3[/sup] + 2 lg 3x = lg x[sup]3[/sup] + lg (3x)[sup]2[/sup] = lg x[sup]3[/sup] + lg 9x[sup]2[/sup] = lg (x[sup]3[/sup]*9x[sup]2[/sup]) = lg 9x[sup]5[/sup], dvs. at
lg 9x[sup]5[/sup] = 4
9x[sup]5[/sup] = 10[sup]4[/sup]
x[sup]5[/sup] = 10[sup]4[/sup]/9
x = (10[sup]4[/sup]/9)[sup]1/5[/sup] ≈ 4,07.