Hvordan løser likningen
2.5 (x--1.2)^5=9.0
løse likning
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Skal det være 1 eller 2 "minuser"?hhae skrev:Hvordan løser likningen
2.5 (x--1.2)^5=9.0
[tex]2.5*(x-1.2)^5=9\\ 5ln(x-1.2)=ln (\frac9 {2.5})\\ ln (x-1.2)=0.256\\ x=e^{0.256}+1.2\\x=2.49[/tex]
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